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Half Angles (C)

It was shown in the last section that

\begin{displaymath}
\cos(2A) = 2\cos^2(A) - 1\end{displaymath}

and

\begin{displaymath}
\cos(2A) = 1-2\sin^2(A).\end{displaymath}

If we let $A = \theta/2$ and solve for sine or cosine of $\theta$ we get the half angle identities:

\begin{displaymath}
\cos^2(\theta/2) = \frac{1+\cos(\theta)}{2}\end{displaymath}

and

\begin{displaymath}
\sin^2(\theta/2) = \frac{1-\cos(\theta)}{2}\end{displaymath}

If the quadrant of $\theta/2$ is known, and the cosine of $\theta$ is known, then the sine and cosine of $\theta/2$ can be computed.

Exercises:

1.
Derive the half angle formulae.
2.
Find the sine and cosine of $\pi/8$.
3.
Find the sine and cosine of $\pi/12$.


Eric S Key
12/30/1999