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Just as there are hidden quadratic equations, there are also hidden
polynomial equations. These are best solved by substitution. Often
the substitution will contribute a side condition. For example, to find all
real numbers x so that
e3x - 4e2x + 5 = 0
we introduce the substitution u = ex which introduces the side condition
u > 0 to go along with the cubic equation
u3 -4u2 + 5 = 0.
Since u3-4u2 + 5 = (u+1)(u2 - 5u+5), the cubic equation in u can be
solved completely. However, there is no x corresonding to u = -1 since
ex = -1 has no solution for x a real number.
Eric S Key
5/8/2001