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From calculus we have the following useful result.
Theorem 2728
If p(z) is a polynomial with real coefficients, a < b and the sign of
p(a) is different from the sign of p(b) then p has a zero between a and
b.
We also have some bits of common sense:
- If all of the exponents in the polynomial p(z) are even or all of the
exponents are odd and p(a) = 0 then p(-a) = 0.
- If all of the coefficents of the polynomial have the same sign, then the
polynomial has no positive roots.
- If all coefficient of the even powered terms of p(z) are positive and
all the odd powered terms have coefficients which are negative, or vice-versa,
then the polynomial has no negative roots.
Exercises
- 1.
- Find all the zeros of each of the following polynomials:
- (a)
- x3-6x2+11x-6;
- (b)
- x4-7x3+17x2-17x + 6;
- (c)
- 10x3-37x2+37x-6;
- (d)
- 5x4 -7x3 - 3x2 + 7x-2;
- (e)
- 54x3-21x2-7x+2;
- (f)
- x4+4x3 + 4x2 - 4x - 5;
- 2.
- Suppose that p(z) = z4 + 3z3 + 2z2 + 3z + 1. Show that
p(i) = 0 and then find all the zeros of p.
Next: Hidden Polynomial Equations and
Up: Solving Polynomial Equations (C)
Previous: Complex Conjugate Root (C)
Eric S Key
5/8/2001