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The tangent function

The domain of the tangent function is a little messy to describe, so let us look at the so-called Principal Tangent Function, ${\rm
Tan}:(-\pi/2,\pi/2)\rightarrow(-\infty,\infty)$, with ${\rm Tan}(x) = \tan(x)$.The formula we derive here will hold for the general tangent function as well. We wish to compute

\begin{displaymath}
{\rm Tan}'(a) \equiv \lim_{h\rightarrow 0}\frac{{\rm Tan}(a+h)-{\rm Tan}(a)}{h}\end{displaymath}

We employ a little algebra:

\begin{displaymath}
\begin{array}
{rcl}
{\displaystyle \frac{{\rm Tan}(a+h)-{\rm...
 ...aystyle \frac{\sin(h)}{h}\frac{1}{\cos(a+h)\cos(a)}}\end{array}\end{displaymath}

so that it is clear that

\begin{displaymath}
\lim_{h\rightarrow 0}\frac{{\rm Tan}(a+h)-{\rm Tan}(a)}{h} =
1\cdot\frac{1}{(\cos(a))^2} = \sec^2(a)\end{displaymath}

so ${\rm Tan}'(a) = \sec^2(a)$, and we show in the same fashion that $\tan'(a)
= \sec^2(a)$. So, for example, the slope of the tangent line to $y=\tan(x)$ at (0,0) is $\sec^2(0) = 1$.



David G Radcliffe
8/18/1998